x^2+36x=2160

Solution for x^2+36x=2160 equation:

x^2+36x=2160

We move all terms to the left:

x^2+36x-(2160)=0

a = 1; b = 36; c = -2160;
Δ = b2-4ac
Δ = 362-4·1·(-2160)
Δ = 9936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9936}=\sqrt{144*69}=\sqrt{144}*\sqrt{69}=12\sqrt{69}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-12\sqrt{69}}{2*1}=\frac{-36-12\sqrt{69}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+12\sqrt{69}}{2*1}=\frac{-36+12\sqrt{69}}{2}
$